Benzene diazonium chloride decomposition help?
Benzene diazonium chloride, C6H5NNCl, decomposes by first order rate law. If the rate constant at 20 C is 4.3*10-5/s, how long will it take for 61% of the compaound to decompose? I saw someone already asked a similar question but the solution was hard to follow. Please help!
The integrated first order equation is:
ln[C6H5NNCl] = ln[C6H5NNCl]o – kt.
The left side of the equation is the concentration of the reactant at any time t, so if 61% of the C6H5NNCl decomposes, then 39% remains. The concentration on the right side of the equation is at time t = 0; so we can let [C6H5NNCl]o = 100 and [C6H5NNCl] = 39. Just substitute;
ln(39) = ln(100) – (4.3*10-5/s) t;
Solving, t = 21,899 s; or about 6 hr 5 min.
The integrated first order equation is:
ln[C6H5NNCl] = ln[C6H5NNCl]o – kt.
The left side of the equation is the concentration of the reactant at any time t, so if 61% of the C6H5NNCl decomposes, then 39% remains. The concentration on the right side of the equation is at time t = 0; so we can let [C6H5NNCl]o = 100 and [C6H5NNCl] = 39. Just substitute;
ln(39) = ln(100) – (4.3*10-5/s) t;
Solving, t = 21,899 s; or about 6 hr 5 min.
References :